Possible Edgic Math Formula to find winner
F (CP) = CP^6/CPP^2 + {(MORP)OTTN)}^3 - UTRP^2F ' (CP) = [CPP^2 x 6CP^5 + CP^6 x 2CPP] / (CPP^2)^2 + {(MORP)OTTN)}^3 - UTRP^2 + (0) (MOR/OTT/UTR) = constantsF ' (CP) = 6CP^5CPP^2 + 2CP^6CPP / CPP^4CP...
View ArticleRe: Possible Edgic Math Formula to find winner
The actual "formula" that exists out there (and it is possible to construct - it's just attainable only through hours and hours of unpaid work) probably functions more like a form of logistic...
View ArticleRe: Possible Edgic Math Formula to find winner
Nothing beats good old intuition in my book (non-math). As RC said, there is way too much noise present to accurately predict a winner. The editors are not incumbents either.
View ArticleRe: Possible Edgic Math Formula to find winner
The problem isn't that there's too much noise. It's that there's not enough data. Survivor would have to air for several hundred years before any robust statistical results could be inferred from the...
View ArticleRe: Possible Edgic Math Formula to find winner
I think this is wrong. The correct formula is. If 2 Returning Contestants. (100% chance that person makes the final 3). If they have a penis odds are they win.
View ArticleRe: Possible Edgic Math Formula to find winner
We've only had 2 instances of that happening and Coach lost, so no.
View ArticleRe: Possible Edgic Math Formula to find winner
"If the pattern is followed correctly, the winner will have exactly 3 CPP episodes over the course of the season. The critical episode is 8th, which will be CP or CPP." "If 2 Returning Contestants....
View ArticleRe: Possible Edgic Math Formula to find winner
You forgot to take into consideration the fact that if a player whose name starts with a 'B' gets a CP5 in a prime numbered episode that you have to double their chances of winning, but only if they...
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